For which of the following sets of quantum nu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum nu

Vedclass · Accepted Answer

$n=4, l=3, m=-1, s=+1/2$

Vedclass · Answer

(B) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum number $(l)$.For option $(A): n+l = 3+2 = 5$.For option $(B): n+l = 4+3 = 7$.For option $(C): n+l = 4+1 = 5$.For option $(D): n+l = 5+0 = 5$.Since the $(n+l)$ value is highest for option $(B)$,the electron in this set has the highest energy.

For which of the following sets of quantum numbers,an electron will have the highest energy?

Similar Questions

The number of electrons that can be accommodated in $d_{z^2}$ orbital is

The shape of $s$-orbital is

The two electrons $X$ and $Y$ have the following sets of quantum numbers:
$X: n=3, l=2, m=-2, s=+1/2$ $Y: n=3, l=0, m=0, s=+1/2$

Which of the following is the correct statement?

Which of the following sets of orbitals may degenerate?

Which of the following pairs of orbitals possess two nodal planes?

Vedclass Test Series

Exam Paper Generator

Online Exam Module